Challenge-36.js

// Given an array of strings words and a string s, determine if s is an acronym of words.

// The string s is considered an acronym of words if it can be formed by concatenating the first character of each string in words in order. For example, "ab" can be formed from ["apple", "banana"], but it can't be formed from ["bear", "aardvark"].

// Return true if s is an acronym of words, and false otherwise.

// Example 1:

// Input: words = ["alice","bob","charlie"], s = "abc"
// Output: true
// Explanation: The first character in the words "alice", "bob", and "charlie" are 'a', 'b', and 'c', respectively. Hence, s = "abc" is the acronym.
// Example 2:

// Input: words = ["an","apple"], s = "a"
// Output: false
// Explanation: The first character in the words "an" and "apple" are 'a' and 'a', respectively.
// The acronym formed by concatenating these characters is "aa".
// Hence, s = "a" is not the acronym.

// Example 3:

// Input: words = ["never","gonna","give","up","on","you"], s = "ngguoy"
// Output: true
// Explanation: By concatenating the first character of the words in the array, we get the string "ngguoy".
// Hence, s = "ngguoy" is the acronym.

//solution

var isAcronym = function (words, s) {
  const acronym = words.map((word) => word.charAt(0)).join("");
  console.log(acronym);
  return acronym === s;
};

isAcronym(["alice", "bob", "charlie"], "abc");