forked from Nandinig24/Leetcode-Solutions
-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy path143
81 lines (72 loc) · 2 KB
/
143
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
class Solution {
public:
void reorderList(ListNode* head) {
if (head == NULL || head->next == NULL) // Handling cases where list is empty or has only one element
return;
vector<int> v;
ListNode* p = head;
// Store values of nodes in the list
while (p != NULL) {
v.push_back(p->val);
p = p->next;
}
p = head;
int i = 0;
int j = v.size() - 1;
while (i <= j) {
p->val = v[i];
p = p->next;
if (i != j) { // Avoid accessing same element twice if list has odd number of elements
p->val = v[j];
p = p->next;
}
i++;
j--;
}
}
};
// class Solution {
// public:
// void reorderList(ListNode* head) {
// ListNode* p=head;
// vector<int>v;
// while(p!=NULL){
// v.push_back(p->val);
// p=p->next;
// }
// if(v.size()%2==0){
// int i=0;
// ListNode* q=head;
// while(q!=NULL){
// q->val=v[i];
// q=q->next;
// // int r=abs(v.size()-i);
// q->val=v[v.size()-i];
// q=q->next;
// i++;
// }
// }
// else{
// int i=0;
// ListNode* q=head;
// while(q->next!=NULL){
// q->val=v[i];
// q=q->next;
// q->val=v[v.size()-i];
// q=q->next;
// i++;
// }
// q->val=v[v.size()/2];
// }
// }
// };