diff --git a/AyushBhandariNITK/Week-1/assignment1.txt b/AyushBhandariNITK/Week-1/assignment1.txt
new file mode 100644
index 0000000..7d4e5b3
--- /dev/null
+++ b/AyushBhandariNITK/Week-1/assignment1.txt
@@ -0,0 +1,95 @@
+1
+
+In the first one
+First output:
+
+['1','S','T','E']
+
+['1','S','T','E']
+
+Reason is that list2=list1 create same object so change in list2 will also create change in list1.
+
+After that list1=list1+[] will create new object for list1.
+So that will change in list2 will not create change in list1.
+
+Second output:
+
+['1','S','T','E']
+
+['1',2,'T','E']
+
+Here for first one reason is same that list2=list1
+
+Here, list1=list1+[] will not create new object for list1. 
+So again change in list2 will affect list1
+
+
+2
+a=[2,3,4,6,5,7,1,8]
+print(a)
+
+b=0
+
+e=0
+
+while(b!=len(a)):
+
+	for i in range(b,8):
+
+		if(a[i]<a[b]):
+
+			c=a[b]
+			
+			a[b]=a[i]
+
+			a[i]=c
+	b+=1
+
+print(a)
+
+print("Which element tou want to find?")
+
+d=int(input())
+
+for i in range(0,len(a)):
+	if(a[i]==d):
+
+		e=1
+
+		break
+
+if(e==1):
+	print("Element is found and position =",i)
+
+else:
+	print("Element is not found")
+
+
+3
+
+Output:
+
+	False
+
+	True
+
+ l1 and l2 are different object.
+ Both str1 and str2 are same object.
+4
+a=int(input("How many number you want ?"))
+
+b=[]
+
+for i in range(0,a):
+
+	b.append(int(input("Enter number")))
+
+print(b)
+
+print("Numbers following condition are")
+
+for i in range(0,a):
+
+	if((b[i]**3)%3==1):
+
+		print(b[i])
diff --git a/AyushBhandariNITK/assignment1.txt b/AyushBhandariNITK/assignment1.txt
new file mode 100644
index 0000000..7d4e5b3
--- /dev/null
+++ b/AyushBhandariNITK/assignment1.txt
@@ -0,0 +1,95 @@
+1
+
+In the first one
+First output:
+
+['1','S','T','E']
+
+['1','S','T','E']
+
+Reason is that list2=list1 create same object so change in list2 will also create change in list1.
+
+After that list1=list1+[] will create new object for list1.
+So that will change in list2 will not create change in list1.
+
+Second output:
+
+['1','S','T','E']
+
+['1',2,'T','E']
+
+Here for first one reason is same that list2=list1
+
+Here, list1=list1+[] will not create new object for list1. 
+So again change in list2 will affect list1
+
+
+2
+a=[2,3,4,6,5,7,1,8]
+print(a)
+
+b=0
+
+e=0
+
+while(b!=len(a)):
+
+	for i in range(b,8):
+
+		if(a[i]<a[b]):
+
+			c=a[b]
+			
+			a[b]=a[i]
+
+			a[i]=c
+	b+=1
+
+print(a)
+
+print("Which element tou want to find?")
+
+d=int(input())
+
+for i in range(0,len(a)):
+	if(a[i]==d):
+
+		e=1
+
+		break
+
+if(e==1):
+	print("Element is found and position =",i)
+
+else:
+	print("Element is not found")
+
+
+3
+
+Output:
+
+	False
+
+	True
+
+ l1 and l2 are different object.
+ Both str1 and str2 are same object.
+4
+a=int(input("How many number you want ?"))
+
+b=[]
+
+for i in range(0,a):
+
+	b.append(int(input("Enter number")))
+
+print(b)
+
+print("Numbers following condition are")
+
+for i in range(0,a):
+
+	if((b[i]**3)%3==1):
+
+		print(b[i])