This method shifts the relevant bit to the zeroth position.
Then we perform AND operation with one which has bit
pattern like 0001. This clears all bits from the original
number except the relevant one. If the relevant bit is one,
the result is 1, otherwise the result is 0.
See getBit.js for further details.
This method shifts 1 over by bitPosition bits, creating a
value that looks like 00100. Then we perform OR operation
that sets specific bit into 1 but it does not affect on
other bits of the number.
See setBit.js for further details.
This method shifts 1 over by bitPosition bits, creating a
value that looks like 00100. Than it inverts this mask to get
the number that looks like 11011. Then AND operation is
being applied to both the number and the mask. That operation
unsets the bit.
See clearBit.js for further details.
This method is a combination of "Clear Bit" and "Set Bit" methods.
See updateBit.js for further details.
This method determines if the number provided is even. It is based on the fact that odd numbers have their last right bit to be set to 1.
Number: 5 = 0b0101
isEven: false
Number: 4 = 0b0100
isEven: true
See isEven.js for further details.
This method determines if the number is positive. It is based on the fact that all positive
numbers have their leftmost bit to be set to 0. However, if the number provided is zero
or negative zero, it should still return false.
Number: 1 = 0b0001
isPositive: true
Number: -1 = -0b0001
isPositive: false
See isPositive.js for further details.
This method shifts original number by one bit to the left. Thus all binary number components (powers of two) are being multiplying by two and thus the number itself is being multiplied by two.
Before the shift
Number: 0b0101 = 5
Powers of two: 0 + 2^2 + 0 + 2^0
After the shift
Number: 0b1010 = 10
Powers of two: 2^3 + 0 + 2^1 + 0
See multiplyByTwo.js for further details.
This method shifts original number by one bit to the right. Thus all binary number components (powers of two) are being divided by two and thus the number itself is being divided by two without remainder.
Before the shift
Number: 0b0101 = 5
Powers of two: 0 + 2^2 + 0 + 2^0
After the shift
Number: 0b0010 = 2
Powers of two: 0 + 0 + 2^1 + 0
See divideByTwo.js for further details.
This method make positive numbers to be negative and backwards. To do so it uses "Twos Complement" approach which does it by inverting all of the bits of the number and adding 1 to it.
1101 -3
1110 -2
1111 -1
0000 0
0001 1
0010 2
0011 3
See switchSign.js for further details.
This method multiplies two signed integer numbers using bitwise operators. This method is based on the following facts:
a * b can be written in the below formats:
0 if a is zero or b is zero or both a and b are zeroes
2a * (b/2) if b is even
2a * (b - 1)/2 + a if b is odd and positive
2a * (b + 1)/2 - a if b is odd and negative
The advantage of this approach is that in each recursive step one of the operands
reduces to half its original value. Hence, the run time complexity is O(log(b) where b is
the operand that reduces to half on each recursive step.
See multiply.js for further details.
This method multiplies two integer numbers using bitwise operators. This method is based on that "Every number can be denoted as the sum of powers of 2".
The main idea of bitwise multiplication is that every number may be split to the sum of powers of two:
I.e.
19 = 2^4 + 2^1 + 2^0
Then multiplying number x by 19 is equivalent of:
x * 19 = x * 2^4 + x * 2^1 + x * 2^0
Now we need to remember that x * 2^4 is equivalent of shifting x left
by 4 bits (x << 4).
See multiplyUnsigned.js for further details.
This method counts the number of set bits in a number using bitwise operators.
The main idea is that we shift the number right by one bit at a time and check
the result of & operation that is 1 if bit is set and 0 otherwise.
Number: 5 = 0b0101
Count of set bits = 2
See countSetBits.js for further details.
This methods outputs the number of bits required to convert one number to another.
This makes use of property that when numbers are XOR-ed the result will be number
of different bits.
5 = 0b0101
1 = 0b0001
Count of Bits to be Flipped: 1
See bitsDiff.js for further details.
To calculate the number of valuable bits we need to shift 1 one bit left each
time and see if shifted number is bigger than the input number.
5 = 0b0101
Count of valuable bits is: 3
When we shift 1 four times it will become bigger than 5.
See bitLength.js for further details.
This method checks if a number provided is power of two. It uses the following
property. Let's say that powerNumber is a number that has been formed as a power
of two (i.e. 2, 4, 8, 16 etc.). Then if we'll do & operation between powerNumber
and powerNumber - 1 it will return 0 (in case if number is power of two).
Number: 4 = 0b0100
Number: 3 = (4 - 1) = 0b0011
4 & 3 = 0b0100 & 0b0011 = 0b0000 <-- Equal to zero, is power of two.
Number: 10 = 0b01010
Number: 9 = (10 - 1) = 0b01001
10 & 9 = 0b01010 & 0b01001 = 0b01000 <-- Not equal to zero, not a power of two.
See isPowerOfTwo.js for further details.