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Hello, extern crate arrayfire as af;
use af::*;
fn main() {
let num_rows: u64 = 4;
let num_cols: u64 = 1;
let dims = Dim4::new(&[num_rows, num_cols, 1, 1]);
let dims1 = Dim4::new(&[1, 1, 1, 1]);
set_backend(Backend::AF_BACKEND_CPU);
let a = iota(dims, dims1, Aftype::F32).unwrap();
println!("a:");
print(&a);
let b = fft(&a, 1.0, num_rows as i64).unwrap();
println!("b:");
print(&b);
let c = ifft(&b, 1.0, num_rows as i64).unwrap();
println!("c:");
print(&c);
} I get the following: Running `target/debug/af_fft`
a:
No Name Array
[4 1 1 1]
0.0000
1.0000
2.0000
3.0000
b:
No Name Array
[4 1 1 1]
(6.0000,0.0000)
(-2.0000,2.0000)
(-2.0000,0.0000)
(-2.0000,-2.0000)
c:
No Name Array
[4 1 1 1]
(0.0000,0.0000)
(4.0000,0.0000)
(8.0000,0.0000)
(12.0000,0.0000) That is instead of the original julia> a = [1, 2, 3, 4]
4-element Array{Int64,1}:
1
2
3
4
julia> b = fft(a)
4-element Array{Complex{Float64},1}:
10.0+0.0im
-2.0+2.0im
-2.0+0.0im
-2.0-2.0im
julia> c = ifft(b)
4-element Array{Complex{Float64},1}:
1.0+0.0im
2.0+0.0im
3.0+0.0im
4.0+0.0im Thanks! |
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Replies: 5 comments
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@alsam As of now, the second parameter in those functions In this situation (1D Array), norm_factor would be number of elements in the Array i.e. 4. |
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Thanks @9prady9 for clarification. |
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Sure, we can add examples. I have created a issue for this. You can follow the progress over here. You may close this issue if all your questions are answered. Thank you for the feedback. |
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Great, thanks! |
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Closing as the question answered. |
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@alsam As of now, the second parameter in those functions
norm_factor
should be used by caller for scaling/normalizing the Arrays. Hence, the output is appearing to be like what it is now.In this situation (1D Array), norm_factor would be number of elements in the Array i.e. 4.