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EditDistance.java
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public class Solution {
public int minDistance(String word1, String word2) {
int n = word1.length();
int m = word2.length();
int[][] dp = new int[n+1][m+1];
for(int i=0; i< m+1; i++){
dp[0][i] = i;
}
for(int i=0; i<n+1; i++){
dp[i][0] = i;
}
for(int i = 1; i<n+1; i++){
for(int j=1; j<m+1; j++){
if(word1.charAt(i-1) == word2.charAt(j-1)){
dp[i][j] = dp[i-1][j-1];
}else{
dp[i][j] = 1 + Math.min(dp[i-1][j-1],Math.min(dp[i-1][j],dp[i][j-1]));
}
}
}
return dp[n][m];
}
}
// 动态规划班版本
public class Solution {
/**
* @param word1 & word2: Two string.
* @return: The minimum number of steps.
*/
public int minDistance(String word1, String word2) {
char[] s1 = word1.toCharArray();
char[] s2 = word2.toCharArray();
int i, j;
int m = s1.length;
int n = s2.length;
int[][] f = new int[m + 1][n + 1];
// commented part is for outputting solution
// 'I', 'D', 'R', 'S'
//char[][] pi = new char[m + 1][n + 1];
for (i = 0; i <= m; ++i) {
for (j = 0; j <= n; ++j) {
if (i == 0) {
f[i][j] = j;
continue;
}
if (j == 0) {
f[i][j] = i;
continue;
}
// i > 0, j > 0
// +1, important!
// delete insert replace
f[i][j] = Math.min(Math.min(f[i - 1][j], f[i][j - 1]), f[i - 1][j - 1]) + 1;
/*if (f[i][j] == f[i - 1][j] + 1) {
pi[i][j] = 'D';
}
else {
if (f[i][j] == f[i][j - 1] + 1) {
pi[i][j] = 'I';
}
else {
pi[i][j] = 'R';
}
}*/
if (s1[i - 1] == s2[j - 1]) {
f[i][j] = Math.min(f[i][j], f[i - 1][j - 1]);
// pi[i][j] = 'S';
}
}
}
/*i = m;
j = n;
while (i > 0 || j > 0) {
if (pi[i][j] == 'D') {
System.out.println("Delete A's " + i + "-th letter from A");
--i;
continue;
}
if (pi[i][j] == 'I') {
System.out.println("Insert B's " + j + "-th letter of B to A");
--j;
continue;
}
if (pi[i][j] == 'R') {
System.out.println("Replace the A's " + i + "-th letter to B's " + j + "-th letter");
--i;
--j;
continue;
}
if (pi[i][j] == 'S') {
--i;
--j;
continue;
}
}*/
return f[m][n];
}
}