diff --git a/exercises/practice/leap/.approaches/boolean-chain/content.md b/exercises/practice/leap/.approaches/boolean-chain/content.md
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+# Chaining Boolean expressions
+
+```scheme
+(define (leap-year? year)
+  (and (zero? (modulo year 4))
+       (or (not (zero? (modulo year 100)))
+           (zero? (modulo year 400)))))
+```
+
+The Boolean expression `(zero? (modulo year 4))` checks the remainder from dividing `year` by 4.
+If a year is evenly divisible by 4, the remainder will be zero.
+[`(zero? n)`][zero] returns the Boolean value `#t` when `n` is zero.
+All leap years are divisible by 4, and this pattern is then repeated whether a year is not divisible by 100 and whether it's divisible by 400.
+[The `and` and `or` forms][and-or] can chain the values from these three Boolean expressions to produce a new value.
+The `and` form produces `#f` if any expression is `#f` or it returns the value of the last expression.
+Any value besides `#f` is equivalent to `#t`.
+The `or` form produces `#f` if all expressions are `#f` or it returns the first non-`#f` value.
+
+| year | divisible by 4 | not divisible by 100 | divisible by 400 |    result    |
+| ---- | -------------- | -------------------  | ---------------- | ------------ |
+| 2020 |             #t |                   #t |    not evaluated |           #t |
+| 2019 |             #f |        not evaluated |    not evaluated |           #f |
+| 2000 |             #t |                   #f |               #t |           #t |
+| 1900 |             #t |                   #f |               #f |           #f |
+
+By situationally skipping some of the tests, we can efficiently calculate the result with fewer operations.
+
+[zero]: https://docs.racket-lang.org/reference/number-types.html#%28def._%28%28quote._~23~25kernel%29._zero~3f%29%29
+[and-or]: https://docs.racket-lang.org/guide/conditionals.html#%28part._and%2Bor%29
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diff --git a/exercises/practice/leap/.approaches/boolean-chain/snippet.txt b/exercises/practice/leap/.approaches/boolean-chain/snippet.txt
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+(define (leap-year? year)
+  (and (zero? (modulo year 4))
+       (or (not (zero? (modulo year 100)))
+           (zero? (modulo year 400)))))
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diff --git a/exercises/practice/leap/.approaches/cond-form/content.md b/exercises/practice/leap/.approaches/cond-form/content.md
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+# Cond form
+
+```scheme
+(define (leap-year? year)
+  (cond
+    [(zero? (modulo year 400)) #t]
+    [(zero? (modulo year 100)) #f]
+    [(zero? (modulo year 4)) #t]
+    [else #f]))
+```
+
+[The cond form][cond-form] sequentially evaluates a series of test expressions until one produces a non-`#f` value.
+Then the associated body for the test expression is evaluated, producing a value.
+At this point, test expression evaluation inside the cond form ends and the value is returned.
+If no test expressions are matched, [void][void-constant] is produced so often
+the last expression is `#t` or `else` which will always be satisfied, allowing a default value to be set.
+
+The cond form can be visualized as a nested [if form][if-form].
+
+```scheme
+(define (leap-year? year)
+  (if (zero? (modulo year 400))
+      #t
+      (if (zero? (modulo year 100))
+          #f
+          (if (zero? (modulo year 4))
+              #t
+              #f))))
+```
+
+To run though how this works, `year` is set to 2024, a leap year.
+
+```scheme
+(zero? (modulo year 400)) ; produces #f so ignored
+(zero? (modulo year 100)) ; produces #f so ignored
+(zero? (modulo year 4)) ; produces #t
+```
+
+The third test expression produces the first non-`#f` value so its body gets evaluated.
+That body contains `#t` which is then the returned value from the cond.
+That value is then returned by the function.
+
+
+[cond-form]: https://docs.racket-lang.org/guide/conditionals.html#%28part._cond%29
+[void-constant]: https://docs.racket-lang.org/reference/void.html#%28def._%28%28quote._~23~25kernel%29._void%29%29
+[if-form]: https://docs.racket-lang.org/reference/if.html
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diff --git a/exercises/practice/leap/.approaches/cond-form/snippet.txt b/exercises/practice/leap/.approaches/cond-form/snippet.txt
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+(define (leap-year? year)
+  (cond
+    [(zero? (modulo year 400)) #t]
+    [(zero? (modulo year 100)) #f]
+    [(zero? (modulo year 4)) #t]
+    [else #f]))
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diff --git a/exercises/practice/leap/.approaches/config.json b/exercises/practice/leap/.approaches/config.json
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+{
+    "introduction": {
+      "authors": [
+        "BNAndras"
+      ]
+    },
+    "approaches": [
+      {
+        "uuid": "b163b6d5-92ed-4073-8169-03e2a1b09fab",
+        "slug": "boolean-chain",
+        "title": "Boolean chain",
+        "blurb": "Use operators to check boolean values in a chain",
+        "authors": [
+          "BNAndras"
+        ]
+      },
+      {
+        "uuid": "22229478-54ce-48ec-867f-1adcf04c42ac",
+        "slug": "cond-form",
+        "title": "Cond",
+        "blurb": "Use the cond form to check boolean values sequentially.",
+        "authors": [
+          "BNAndras"
+        ]
+      },
+      {
+        "uuid": "45f28b96-4803-424c-9973-f2b4445f7227",
+        "slug": "pattern-matching",
+        "title": "Pattern matching",
+        "blurb": "Use the match form to check a list of boolean values at once.",
+        "authors": [
+          "BNAndras"
+        ]
+      }
+    ]
+}
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diff --git a/exercises/practice/leap/.approaches/introduction.md b/exercises/practice/leap/.approaches/introduction.md
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+# Introduction
+
+There are several idiomatic ways to solve this exercise.
+
+## General guidance
+
+Regardless of the approach chosen, this exercise requires students to use Boolean logic to decide if a given year is a leap year.
+
+## Approach: Boolean chaining
+
+```scheme
+(define (leap-year? year)
+  (and (zero? (modulo year 4))
+       (or (not (zero? (modulo year 100)))
+           (zero? (modulo year 400)))))
+```
+
+For more information, check the [Boolean chain approach][approach-boolean-chain].
+
+## Approach: Cond form
+
+```scheme
+(define (leap-year? year)
+  (cond
+    [(zero? (modulo year 400)) #t]
+    [(zero? (modulo year 100)) #f]
+    [(zero? (modulo year 4)) #t]
+    [else #f]))
+```
+
+For more information, check the [cond form approach][approach-cond-form].
+
+## Approach: Pattern matching
+
+```scheme
+(define (leap-year? year)
+  (define divisible-by-4 (zero? (modulo year 4)))
+  (define divisible-by-100 (zero? (modulo year 100)))
+  (define divisible-by-400 (zero? (modulo year 400))) 
+  (match (list divisible-by-4 divisible-by-100 divisible-by-400)
+    [(list _ _ #t) #t]
+    [(list _ #t _) #f]
+    [(list #t _ _) #t]
+    [_ #f]))
+```
+
+For more information, check the [pattern matching approach][approach-pattern-matching].
+
+[approach-boolean-chain]: https://exercism.org/tracks/racket/exercises/leap/approaches/boolean-chain
+[approach-cond-form]: https://exercism.org/tracks/racket/exercises/leap/cond-form
+[approach-pattern-matching]: https://exercism.org/tracks/racket/exercises/leap/approaches/pattern-matching
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diff --git a/exercises/practice/leap/.approaches/pattern-matching/content.md b/exercises/practice/leap/.approaches/pattern-matching/content.md
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+# Pattern matching
+
+```scheme
+(define (leap-year? year)
+  (define divisible-by-4 (zero? (modulo year 4)))
+  (define divisible-by-100 (zero? (modulo year 100)))
+  (define divisible-by-400 (zero? (modulo year 400))) 
+  (match (list divisible-by-4 divisible-by-100 divisible-by-400)
+    [(list _ _ #t) #t]
+    [(list _ #t _) #f]
+    [(list #t _ _) #t]
+    [_ #f]))
+```
+
+[The match form][match-form] compares an expression sequentially to a series of clauses that contain patterns describing the contents of that expression and values returned when a given pattern is matched.
+For this exercise, this takes the form of creating a list containing three Boolean values representing whether a year is divisible by 4, 100, or 400.
+As an example, let's run through this code assuming `year` is set to 1993.
+`(divisible-by-4 1999)` is `#f`, `(divisible-by-100 1999)` is `#f`, and `(divisible-by-400 1999)` is `#f`.
+Filling in these results below, we have four patterns underneath it:
+
+```scheme
+(match (list #t #f #f) ; assuming the year is 1999
+  [(list _ _ #t) #t]
+  [(list _ #t _) #f]
+  [(list #t _ _) #t]
+  [_ #f])
+```
+
+The first three expect a list of three elements (`_` matching any value), but they differ on which value in the pattern can only be the literal value `#t`.
+
+The first clause `[(list _ _ #t) #t]` describes a series of checks where the year must at least be divisible by 400.
+A year divisible by 400 is also divisible by 4 and 100 so we can safely assume all three checks returned `#t` and there's no need to specify the result.
+If this pattern is matched, `#t` is returned.
+1999 isn't divisible by 400 since the `#f` in the third position means the pattern isn't matched.
+
+The second clause `[(list _ #t _) #f]` describes a series of checks where the year must at least be divisible by 100.
+A year divisible by 100 is also divisible by 4 so we can be sure that other check returned true and there's no need to specify it here.
+We can also assume a year divisible by 100 wouldn't be divisible by 400 because if it were, the previous pattern would have already matched.
+If this pattern is matched, `#f` is returned.
+1999 isn't divisible by 100 since `#f` in the second position means the pattern isn't matched.
+
+The third clause `[(list #t _ _) #t]` describes a series of checks where the year must at least be divisible by 4.
+If this pattern is matched, `#t` is returned.
+1999 isn't divisible by 4 since `#f` in the first position means the pattern isn't matched.
+
+The fourth clause `[_ #f]` features a pattern with a single `_`, which means any value at all can match this pattern. 
+Without such a clause, an exception will occur if none of the clauses' patterns matched.
+1999 isn't divisible by 4, 100, or 400, but it matches this catch-all pattern after not matching the previous patterns.
+As a result, `#f` is returned by the code.
+
+[match-form]: https://docs.racket-lang.org/guide/match.html
diff --git a/exercises/practice/leap/.approaches/pattern-matching/snippet.txt b/exercises/practice/leap/.approaches/pattern-matching/snippet.txt
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+(define (leap-year? year)
+  (match (list (zero? (modulo year 4)) (zero? (modulo year 100)) (zero? (modulo year 400)))
+    [(list _ _ #t) #t]
+    [(list _ #t _) #f]
+    [(list #t _ _) #t]
+    [_ #f]))
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