apparently.js

// For every string, after every occurrence of 'and' and/or 'but', insert the substring 'apparently' directly after the occurrence(s).

// If input does not contain 'and' or 'but', return the same string. If a blank string, return ''.

// If substring 'apparently' is already directly after an 'and' and/or 'but', do not add another. (Do not add duplicates).

// Examples:
// Input 1

// 'It was great and I've never been on live television before but sometimes I don't watch this.'
// Output 1

// 'It was great and apparently I've never been on live television before but apparently sometimes I don't watch this.'
// Input 2

// 'but apparently'
// Output 2

// 'but apparently'
// (no changes because 'apparently' is already directly after 'but' and there should not be a duplicate.)

// An occurrence of 'and' and/or 'but' only counts when it is at least one space separated. For example 'andd' and 'bbut' do not count as occurrences, whereas 'b but' and 'and d' does count.

function apparently(string) {
  if (!string) return "";

  return string
    .split(" ")
    .map((val, i, arr) => {
      if ((val === "and" || val === "but") && arr[i + 1] !== "apparently") {
        return val + " apparently";
      } else {
        return val;
      }
    })
    .join(" ");
}