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Trying to do $database->ref('some/path')->orderByChild('childname').equalTo('stringvalue')->...
Will throw an error: "Constraint index field must be a JSON primitive".
So it seems strings don't work, but performing the same query in, say, javascript Firebase, is allowed with strings.
The text was updated successfully, but these errors were encountered:
@Mogball See https://stackoverflow.com/a/41991196/10728554 or #58 about adding quotes around your strings.
Also the updated documentation has a case for this https://github.com/ktamas77/firebase-php#supported-commands.
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Adding to @Masref
The key value must also be json encoded:
$key =json_encode("206"); $value = $firebase->get($path, array('orderBy' => '"url"', 'equalTo' => $key));
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Trying to do $database->ref('some/path')->orderByChild('childname').equalTo('stringvalue')->...
Will throw an error: "Constraint index field must be a JSON primitive".
So it seems strings don't work, but performing the same query in, say, javascript Firebase, is allowed with strings.
The text was updated successfully, but these errors were encountered: