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Using allow after valid is not working #494

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Pnlvfx opened this issue Dec 4, 2024 · 1 comment

Pnlvfx commented Dec 4, 2024 •

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Describe the bug
If you add the allow operator after using the valid it will only pick the valid.

example:

export const ciaoSchema = Joi.string().valid('Ciao').allow(null).meta({className: 'Data'})

will output:

type Data = 'Ciao'

instead of:

type Data = 'Ciao' | null

Author

Pnlvfx commented Dec 4, 2024

Describe the bug If you add the allow operator after using the valid it will only pick the valid.

example:

export const ciaoSchema = Joi.string().valid('Ciao').allow(null).meta({className: 'Data'})

will output:

type Data = 'Ciao'

instead of:

type Data = 'Ciao' | null

I know That I can add the null on the valid, but when you have a reusable type it's not always possible to do so.

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