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import StringIO
to
import io
go to line 11 and change from cgi import escape to from html import escape
from cgi import escape
from html import escape
Add this below line 11 import html
import html
Go to line 4 in handler.py and change urlparse to urlib.parse
urlparse
urlib.parse
The text was updated successfully, but these errors were encountered:
Use urllib.parse and not urlib.parse
This will solve the issue
Sorry, something went wrong.
I get the following error pycurl.error: (23, 'failure writing output to destination')
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solution for StringIO issue in safeurl.py
import StringIO
to
import io
Now open handler.py and do following
go to line 11 and change
from cgi import escape
to
from html import escape
Add this below line 11
import html
Go to line 4 in handler.py and change
urlparse
to
urlib.parse
The text was updated successfully, but these errors were encountered: