Class Exercise - conditionals_if_elif_else.ipynb

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    "raining = input(\"Is it raining (yes/no)? \")\n",
    "if raining == \"yes\":\n",
    "  print(\"You should take the bus to work.\")\n",
    "if raining == \"no\":\n",
    "  print(\"You should walk to work.\")"
   ]
  },
  {
   "cell_type": "code",
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    "'''\n",
    "Assignment vs comparison\n",
    "\n",
    "A single = is used for assignment. This is what we do to set variables.\n",
    " The first line of the program above is setting the variable name to the value \"Grok\" using a single equals sign.\n",
    "\n",
    "A double == is used for comparison. This is what we do to check whether two things are equal.\n",
    " The second line of the program above is checking whether the variable name is equal to \"Grok\" using a double equals sign.\n",
    "'''\n",
    "\n",
    "name = \"samarth\"\n",
    "if name == \"samarth\":\n",
    "  print(\"Hello, friend\")"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": [
    "#syntax error\n",
    "name = \"samarth\"\n",
    "if name = \"samarth\":\n",
    "  print(\"Hello, friend\")"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
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   "source": [
    "\"\"\"\n",
    "You are trying to log in to your old computer, and can't remember the password. \n",
    "You sit for hours making random guesses... I'm sure you thought it was funny back when you came up with that password (chEEzburg3rz).\n",
    "\n",
    "Write a program that tells you whether your guess is correct. If it is correct, it should grant access like this:\n",
    "\n",
    "Enter password: chEEzburg3rz\n",
    "Access granted\n",
    "\n",
    "Enter password: lolcatZ\n",
    "Access denied\n",
    "\"\"\""
   ]
  },
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    "colab": {
     "base_uri": "https://localhost:8080/"
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    "id": "_rNbLUwTfLEb",
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    "'''\n",
    "The simplest kind of if statement has one test and one action:\n",
    "if conditional_test:\n",
    "    do something\n",
    "'''\n",
    "# To Take care of Indentation\n",
    "\n",
    "age = 19\n",
    "if age >= 18:\n",
    "  print(\"You are eligible to vote!\")\n",
    "\n"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": [
    "#Two print statement in if block will be printed provided if condition is satisfied\n",
    "#To be placed exactly in same vertical line\n",
    "\n",
    "age = 19\n",
    "if age >= 18:\n",
    "  print(\"You are eligible to vote!\")\n",
    "  print(\"Voting is responsibility of every citizen !\")"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
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   "source": [
    "#Two print statement in if block, to be placed exactly in same vertical line\n",
    "#The Third print statement will be printed irrespective of the if block\n",
    "\n",
    "age = 14\n",
    "if age >= 18:\n",
    "  print(\"You are eligible to vote!\")\n",
    "  print(\"Voting is responsibility of every citizen !\")\n",
    "\n",
    "print(\"Be a good citizen of your country!\")  \n",
    "\n"
   ]
  },
  {
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    "'''\n",
    "Class Exercise\n",
    "\n",
    "\n",
    "Using the if Statement\n",
    "\n",
    "Kathryn teaches a science class and her students are required to take three tests. She wants\n",
    "to write a program that her students can use to calculate their average test score. She also\n",
    "wants the program to congratulate the student enthusiastically if the average is greater\n",
    "than 95. Here is the algorithm in pseudocode:\n",
    "\n",
    "Get the first test score\n",
    "Get the second test score\n",
    "Get the third test score\n",
    "Calculate the average\n",
    "Display the average\n",
    "If the average is greater than 95:\n",
    "    Congratulate the user\n",
    "'''\n",
    "\n",
    "# This program gets three test scores and displays\n",
    "# their average.  It congratulates the user if the\n",
    "# average is a high score.\n",
    "\n",
    "# The high score variable holds the value that is\n",
    "# considered a high score.\n",
    "high_score = 95\n",
    " \n",
    "# Get the three test scores.\n",
    "test1 = int(input('Enter the score for test 1: '))\n",
    "test2 = int(input('Enter the score for test 2: '))\n",
    "test3 = int(input('Enter the score for test 3: '))\n",
    "\n",
    "# Calculate the average test score.\n",
    "average = (test1 + test2 + test3) / 3\n",
    "\n",
    "# Print the average.\n",
    "print(f'The average score is {average}.')\n",
    "\n",
    "# If the average is a high score,\n",
    "# congratulate the user.\n",
    "if average >= high_score:\n",
    "    print('Congratulations!')\n",
    "    print('That is a great average!')\n",
    "\n"
   ]
  },
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   "source": [
    "'''\n",
    "An if-else block is similar to a simple if statement, but the else statement\n",
    "allows you to define an action or set of actions that are executed when the\n",
    "conditional test fails.\n",
    "\n",
    "The last print statement is printed irrespective of the if and else statement\n",
    "'''\n",
    "age = 17\n",
    "if age >= 18:\n",
    "  print(\"You are old enough to vote!\")\n",
    "  print(\"Have you registered to vote yet?\")\n",
    "else:\n",
    "  print(\"Sorry, you are too young to vote.\")\n",
    "  print(\"Please register to vote as soon as you turn 18!\")\n",
    "\n",
    "\n",
    "print(\"Be a good citizen of your country!\")    "
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": [
    "#Check if the number is odd or even\n",
    "\n",
    "number = input(\"Enter a number, and I'll tell you if it's even or odd: \")\n",
    "number = int(number)\n",
    "if number % 2 == 0:\n",
    "  print(f\"\\nThe number {number} is even.\")\n",
    "else:\n",
    "  print(f\"\\nThe number {number} is odd.\")"
   ]
  },
  {
   "cell_type": "code",
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    "'''\n",
    "Class Exercise:\n",
    "\n",
    "Chris owns an auto repair business and has several employees. If any employee works over\n",
    "40 hours in a week, he pays them 1.5 times their regular hourly pay rate for all hours over\n",
    "40. He has asked you to design a simple payroll program that calculates an employee’s\n",
    "gross pay, including any overtime wages. \n",
    "\n",
    "You design the following algorithm:\n",
    "\n",
    "Get the number of hours worked.\n",
    "Get the hourly pay rate.\n",
    "\n",
    "If the employee worked more than 40 hours:\n",
    "\tCalculate and display the gross pay with overtime.\n",
    "Else:\n",
    "\tCalculate and display the gross pay as usual.\n",
    "    \n",
    "'''    \n",
    "# Variables to represent the base hours and\n",
    "# the overtime multiplier.\n",
    "base_hours = 40       # Base hours per week\n",
    "ot_multiplier = 1.5   # Overtime multiplier\n",
    "\n",
    "# Get the hours worked and the hourly pay rate.\n",
    "hours = float(input('Enter the number of hours worked: '))\n",
    "pay_rate = float(input('Enter the hourly pay rate: '))\n",
    "\n",
    "# Calculate and display the gross pay.\n",
    "if hours > base_hours:\n",
    "    # Calculate the gross pay with overtime.\n",
    "    # First, get the number of overtime hours worked.\n",
    "    overtime_hours = hours - base_hours\n",
    "\n",
    "    # Calculate the amount of overtime pay.\n",
    "    overtime_pay = overtime_hours * pay_rate * ot_multiplier\n",
    "\n",
    "    # Calculate the gross pay.\n",
    "    gross_pay = base_hours * pay_rate + overtime_pay\n",
    "else:\n",
    "    # Calculate the gross pay without overtime.\n",
    "    gross_pay = hours * pay_rate\n",
    "\n",
    "# Display the gross pay.\n",
    "print(f'The gross pay is ${gross_pay:,.2f}.')"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": [
    "#Decisions with multiple options\n",
    "\n",
    "x = 5\n",
    "if x < 3:\n",
    "  print(\"x is less than three\")\n",
    "else:\n",
    "  if x == 3:\n",
    "    print(\"x is equal to three\")\n",
    "  else:\n",
    "    print(\"x is greater than three\")"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": [
    "#Decisions with multiple options using elif\n",
    "\n",
    "x = 5\n",
    "if x < 3:\n",
    "  print(\"x is less than three\")\n",
    "elif x == 3:\n",
    "  print(\"x is equal to three\")\n",
    "else:\n",
    "  print(\"x is greater than three\")"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {
    "id": "YMx7m3yG6Rzj"
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    "'''\n",
    "Many real-world situations involve more than two possible conditions.\n",
    "For example, consider an amusement park that charges different rates for\n",
    "different age groups:\n",
    "• Admission for anyone under age 4 is free.\n",
    "• Admission for anyone between & including the ages of 4 and 20 is $25.\n",
    "• Admission for anyone between & including the ages of 21 and 40 is $30.\n",
    "• Admission for anyone between & including the ages of 41 and 70 is $20.\n",
    "• Admission for anyone with age greater than its 5$\n",
    "\n",
    "'''\n",
    "\n",
    "# Three different ways to write the same logic\n",
    "\n",
    "age = int(input(\"Enter the Visitor's age\"))\n",
    "if age < 4:\n",
    "  price = 0\n",
    "elif age >= 4 and age <= 20:\n",
    "  price = 25\n",
    "elif age >= 21 and age <= 40:\n",
    "  price = 30\n",
    "elif age >= 41 and age <= 70:\n",
    "  price = 20  \n",
    "else:\n",
    "  price = 5  \n",
    "  \n",
    "print(f\"Your admission cost is ${price}.\")\n",
    "\n"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": [
    "age = int(input(\"Enter the Visitor's age\"))\n",
    "if age < 4:\n",
    "  price = 0\n",
    "elif age < 21:\n",
    "  price = 25\n",
    "elif age < 41:\n",
    "  price = 30\n",
    "elif age < 71:\n",
    "  price = 20  \n",
    "else:\n",
    "  price = 5  \n",
    "  \n",
    "print(f\"Your admission cost is ${price}.\")"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": [
    "# Difference between if elif else & all the ifs\n",
    "# All the if will be evaluated or run to calculate the answer when we have allifs\n",
    "# In if elif else , the program will exit when the condition is satisfied and will save computer time & be optimal.\n",
    "\n",
    "age = int(input(\"Enter the Visitor's age\"))\n",
    "if age < 4:\n",
    "  price = 0\n",
    "if age >= 4 and age <= 20:\n",
    "  price = 25\n",
    "if age >= 21 and age <= 40:\n",
    "  price = 30\n",
    "if age >= 41 and age <= 70:\n",
    "  price = 20  \n",
    "if age >= 71:\n",
    "  price = 5  \n",
    "  \n",
    "print(f\"Your admission cost is ${price}.\")"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": [
    "#ATM Machine"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": [
    "'''\n",
    "Nested Ifs:\n",
    "\n",
    "Take care of Indentation :\n",
    "\n",
    ">Make sure each else clause is aligned with its matching if clause.\n",
    ">Make sure the statements in each block are consistently indented.\n",
    "\n",
    "Class Exercise:\n",
    "\n",
    "Consider a program that determines whether a bank customer qualifies for a loan.\n",
    "To qualify, two conditions must exist: \n",
    "(1) the customer must earn at leas $30,000 per year, and \n",
    "(2) the customer must have been employed for at least two years.\n",
    "\n",
    "'''\n",
    "\n",
    "# This program determines whether a bank customer\n",
    "# qualifies for a loan.\n",
    "\n",
    "MIN_SALARY = 30000.0  # The minimum annual salary\n",
    "MIN_YEARS = 2         # The minimum years on the job\n",
    "\n",
    "# Get the customer's annual salary.\n",
    "salary = float(input('Enter your annual salary: '))\n",
    "\n",
    "# Get the number of years on the current job.\n",
    "years_on_job = int(input('Enter the number of ' +\n",
    "                         'years employed: '))\n",
    "\n",
    "# Determine whether the customer qualifies.\n",
    "if salary >= MIN_SALARY:\n",
    "    if years_on_job >= MIN_YEARS:\n",
    "        print('You qualify for the loan.')\n",
    "    else:\n",
    "        print(f'You must have been employed '\n",
    "              f'for at least {MIN_YEARS} '\n",
    "              f'years to qualify.')\n",
    "else:\n",
    "    print(f'You must earn at least $'\n",
    "          f'{MIN_SALARY:,.2f} '\n",
    "          f'per year to qualify.')\n"
   ]
  },
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   "cell_type": "code",
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   "source": [
    "# Another Way to write the same above given program.\n",
    "# This program determines whether a bank customer qualifies for a loan.\n",
    "\n",
    "min_salary = 30000.0  # The minimum annual salary\n",
    "min_years = 2         # The minimum years on the job\n",
    "\n",
    "# Get the customer's annual salary.\n",
    "salary = float(input('Enter your annual salary: '))\n",
    "\n",
    "# Get the number of years on the current job.\n",
    "years_on_job = int(input('Enter the number of ' +\n",
    "                         'years employed: '))\n",
    "\n",
    "# Determine whether the customer qualifies.\n",
    "if salary >= min_salary and years_on_job >= min_years:\n",
    "    print('You qualify for the loan.')\n",
    "else:\n",
    "    print('You do not qualify for this loan.')\n",
    "\n"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 1,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "2004 is a leap year\n"
     ]
    }
   ],
   "source": [
    "\"\"\"\n",
    "Identify if a Year is Leap or not..\n",
    "\n",
    "\"\"\"\n",
    "# Python program to check if year is a leap year or not\n",
    "\n",
    "print(\"Leap year comes every 4 years, but that's not always True.\")\n",
    "\n",
    "print('\\n2004, 2008 2012, 2016, 2020, 2000, 2400 are leap years but 2100, 2200, 2300 are not.')\n",
    "\n",
    "year = int(input(\"\\nEnter the year to be checked for Leap Year\"))\n",
    "\n",
    "# To get year (integer input) from the user\n",
    "# year = int(input(\"Enter a year: \"))\n",
    "\n",
    "if (year % 4) == 0:\n",
    "   if (year % 100) == 0:\n",
    "       if (year % 400) == 0:\n",
    "           print(f\"{year} is a leap year\")\n",
    "       else:\n",
    "           print(f\"{year} is not a leap year\")\n",
    "   else:\n",
    "       print(f\"{year} is a leap year\")\n",
    "else:\n",
    "   print(f\"{year} is not a leap year\")\n"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 1,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "your year is 2000\n",
      "it may be a leap year\n",
      "it is definitely a leap year - 2000, 2400, 2800\n"
     ]
    }
   ],
   "source": [
    "year = int(input(\"Enter a year to check if its a leap year or not\"))\n",
    "print(f'your year is {year}')\n",
    "\n",
    "if year % 4 ==  0 :\n",
    "\tprint('it may be a leap year')\n",
    "\n",
    "\tif year % 100 ==  0 :\n",
    "\t\tif year % 400 ==  0 :\n",
    "\t\t\tprint('it is definitely a leap year - 2000, 2400, 2800')\n",
    "\t\telse:\n",
    "\t\t\tprint('it is definitely not a leap year - 2100, 2200, 2300')\n",
    "\n",
    "\telse:\n",
    "\t\tprint('it is defintely a leap year - 2004, 2008, 2020')\t\n",
    "\t\n",
    "else:\n",
    "\tprint('its is definitely not a leap year')\n",
    "\t"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 2,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "\n",
      "You chose rock, computer chose paper.\n",
      "\n",
      "Paper covers rock! You lose.\n"
     ]
    }
   ],
   "source": [
    "\n",
    "'''\n",
    "Rock, Paper, Scissors\n",
    "\n",
    "'''\n",
    "\n",
    "import random\n",
    "\n",
    "user_action = input(\"Enter a choice (rock, paper, scissors): \")\n",
    "possible_actions = [\"rock\", \"paper\", \"scissors\"]\n",
    "computer_action = random.choice(possible_actions)\n",
    "print(f\"\\nYou chose {user_action}, computer chose {computer_action}.\\n\")\n",
    "\n",
    "if user_action == computer_action:\n",
    "    print(f\"Both players selected {user_action}. It's a tie!\")\n",
    "\n",
    "elif user_action == \"rock\":\n",
    "    if computer_action == \"scissors\":\n",
    "        print(\"Rock smashes scissors! You win!\")\n",
    "    else:\n",
    "        print(\"Paper covers rock! You lose.\")\n",
    "\n",
    "elif user_action == \"paper\":\n",
    "    if computer_action == \"rock\":\n",
    "        print(\"Paper covers rock! You win!\")\n",
    "    else:\n",
    "        print(\"Scissors cuts paper! You lose.\")\n",
    "        \n",
    "elif user_action == \"scissors\":\n",
    "    if computer_action == \"paper\":\n",
    "        print(\"Scissors cuts paper! You win!\")\n",
    "    else:\n",
    "        print(\"Rock smashes scissors! You lose.\") "
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": [
    "\"\"\"\n",
    "Largest of 3 Numbers\n",
    "\n",
    "\"\"\"\n",
    "\n",
    "# Python program to find the largest number among the three input numbers\n",
    "\n",
    "# change the values of num1, num2 and num3\n",
    "# for a different result\n",
    "num1 = 10\n",
    "num2 = 14\n",
    "num3 = 12\n",
    "\n",
    "# uncomment following lines to take three numbers from user\n",
    "#num1 = float(input(\"Enter first number: \"))\n",
    "#num2 = float(input(\"Enter second number: \"))\n",
    "#num3 = float(input(\"Enter third number: \"))\n",
    "\n",
    "if (num1 >= num2) and (num1 >= num3):\n",
    "   largest = num1\n",
    "elif (num2 >= num1) and (num2 >= num3):\n",
    "   largest = num2\n",
    "else:\n",
    "   largest = num3\n",
    "\n",
    "print(\"The largest number is\", largest)\n"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 4,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "**************************\n",
      "***Rock Paper Scissors****\n",
      "**************************\n",
      "User needs to enter one of these 3 options:\n",
      "For Rock     :r\n",
      "For Paper    :p\n",
      "For Scissors :s\n",
      "s\n",
      "paper\n"
     ]
    }
   ],
   "source": [
    "import random\n",
    "\n",
    "print(\"**************************\")\n",
    "print(\"***Rock Paper Scissors****\")\n",
    "print(\"**************************\")\n",
    "\n",
    "print(\"User needs to enter one of these 3 options:\")\n",
    "print(\"For Rock     :r\")\n",
    "print(\"For Paper    :p\")\n",
    "print(\"For Scissors :s\")\n",
    "\n",
    "winner = ''\n",
    "userChoice = input(\"Enter your choice to play the game\")\n",
    "\n",
    "possible_options = ['rock','paper','scissor']\n",
    "\n",
    "compChoice = random.choice(possible_options)\n",
    "\n",
    "print(userChoice)\n",
    "\n",
    "if compChoice == 'rock':\n",
    "    compChoice = 'r'\n",
    "elif compChoice == 'paper':  \n",
    "    compChoice = 'p'\n",
    "else:\n",
    "    compChoice = 's'    \n",
    "\n",
    "\n",
    "if userChoice == compChoice:\n",
    "    winner = 'Its a Tie!!'\n",
    "\n",
    "elif userChoice == 'r':\n",
    "    if compChoice == 'p':\n",
    "        winner = 'Computer Wins'\n",
    "    elif compChoice == 's': \n",
    "        winner = 'User Wins'   \n",
    "\n",
    "\n",
    "elif userChoice == 'p':\n",
    "    if compChoice == 'p':\n",
    "        winner = 'Computer Wins'\n",
    "    elif compChoice == 's': \n",
    "        winner = 'User Wins'      \n",
    "\n",
    "\n",
    "elif userChoice == 's':\n",
    "    if compChoice == 'p':\n",
    "        winner = 'Computer Wins'\n",
    "    elif compChoice == 's': \n",
    "        winner = 'User Wins'   \n",
    "\n",
    "\n",
    "print(winner)        \n",
    "\n",
    "  \n"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 6,
   "metadata": {},
   "outputs": [
    {
     "ename": "KeyboardInterrupt",
     "evalue": "Interrupted by user",
     "output_type": "error",
     "traceback": [
      "\u001b[1;31m---------------------------------------------------------------------------\u001b[0m",
      "\u001b[1;31mKeyboardInterrupt\u001b[0m                         Traceback (most recent call last)",
      "\u001b[1;32m~\\AppData\\Local\\Temp/ipykernel_10516/365325528.py\u001b[0m in \u001b[0;36m<module>\u001b[1;34m\u001b[0m\n\u001b[0;32m      1\u001b[0m \u001b[0ma\u001b[0m \u001b[1;33m=\u001b[0m \u001b[0minput\u001b[0m\u001b[1;33m(\u001b[0m\u001b[1;33m)\u001b[0m\u001b[1;33m\u001b[0m\u001b[1;33m\u001b[0m\u001b[0m\n\u001b[0;32m      2\u001b[0m \u001b[0mb\u001b[0m \u001b[1;33m=\u001b[0m \u001b[0minput\u001b[0m\u001b[1;33m(\u001b[0m\u001b[1;33m)\u001b[0m\u001b[1;33m\u001b[0m\u001b[1;33m\u001b[0m\u001b[0m\n\u001b[1;32m----> 3\u001b[1;33m \u001b[0mc\u001b[0m \u001b[1;33m=\u001b[0m \u001b[0minput\u001b[0m\u001b[1;33m(\u001b[0m\u001b[1;33m)\u001b[0m\u001b[1;33m\u001b[0m\u001b[1;33m\u001b[0m\u001b[0m\n\u001b[0m\u001b[0;32m      4\u001b[0m \u001b[1;33m\u001b[0m\u001b[0m\n\u001b[0;32m      5\u001b[0m \u001b[1;33m\u001b[0m\u001b[0m\n",
      "\u001b[1;32m~\\AppData\\Local\\Programs\\Python\\Python310\\lib\\site-packages\\ipykernel\\kernelbase.py\u001b[0m in \u001b[0;36mraw_input\u001b[1;34m(self, prompt)\u001b[0m\n\u001b[0;32m   1005\u001b[0m                 \u001b[1;34m\"raw_input was called, but this frontend does not support input requests.\"\u001b[0m\u001b[1;33m\u001b[0m\u001b[1;33m\u001b[0m\u001b[0m\n\u001b[0;32m   1006\u001b[0m             )\n\u001b[1;32m-> 1007\u001b[1;33m         return self._input_request(\n\u001b[0m\u001b[0;32m   1008\u001b[0m             \u001b[0mstr\u001b[0m\u001b[1;33m(\u001b[0m\u001b[0mprompt\u001b[0m\u001b[1;33m)\u001b[0m\u001b[1;33m,\u001b[0m\u001b[1;33m\u001b[0m\u001b[1;33m\u001b[0m\u001b[0m\n\u001b[0;32m   1009\u001b[0m             \u001b[0mself\u001b[0m\u001b[1;33m.\u001b[0m\u001b[0m_parent_ident\u001b[0m\u001b[1;33m[\u001b[0m\u001b[1;34m\"shell\"\u001b[0m\u001b[1;33m]\u001b[0m\u001b[1;33m,\u001b[0m\u001b[1;33m\u001b[0m\u001b[1;33m\u001b[0m\u001b[0m\n",
      "\u001b[1;32m~\\AppData\\Local\\Programs\\Python\\Python310\\lib\\site-packages\\ipykernel\\kernelbase.py\u001b[0m in \u001b[0;36m_input_request\u001b[1;34m(self, prompt, ident, parent, password)\u001b[0m\n\u001b[0;32m   1050\u001b[0m             \u001b[1;32mexcept\u001b[0m \u001b[0mKeyboardInterrupt\u001b[0m\u001b[1;33m:\u001b[0m\u001b[1;33m\u001b[0m\u001b[1;33m\u001b[0m\u001b[0m\n\u001b[0;32m   1051\u001b[0m                 \u001b[1;31m# re-raise KeyboardInterrupt, to truncate traceback\u001b[0m\u001b[1;33m\u001b[0m\u001b[1;33m\u001b[0m\u001b[0m\n\u001b[1;32m-> 1052\u001b[1;33m                 \u001b[1;32mraise\u001b[0m \u001b[0mKeyboardInterrupt\u001b[0m\u001b[1;33m(\u001b[0m\u001b[1;34m\"Interrupted by user\"\u001b[0m\u001b[1;33m)\u001b[0m \u001b[1;32mfrom\u001b[0m \u001b[1;32mNone\u001b[0m\u001b[1;33m\u001b[0m\u001b[1;33m\u001b[0m\u001b[0m\n\u001b[0m\u001b[0;32m   1053\u001b[0m             \u001b[1;32mexcept\u001b[0m \u001b[0mException\u001b[0m\u001b[1;33m:\u001b[0m\u001b[1;33m\u001b[0m\u001b[1;33m\u001b[0m\u001b[0m\n\u001b[0;32m   1054\u001b[0m                 \u001b[0mself\u001b[0m\u001b[1;33m.\u001b[0m\u001b[0mlog\u001b[0m\u001b[1;33m.\u001b[0m\u001b[0mwarning\u001b[0m\u001b[1;33m(\u001b[0m\u001b[1;34m\"Invalid Message:\"\u001b[0m\u001b[1;33m,\u001b[0m \u001b[0mexc_info\u001b[0m\u001b[1;33m=\u001b[0m\u001b[1;32mTrue\u001b[0m\u001b[1;33m)\u001b[0m\u001b[1;33m\u001b[0m\u001b[1;33m\u001b[0m\u001b[0m\n",
      "\u001b[1;31mKeyboardInterrupt\u001b[0m: Interrupted by user"
     ]
    }
   ],
   "source": [
    "a = input()\n",
    "b = input()\n",
    "c = input()\n",
    "\n",
    "\n",
    "\n",
    "\n",
    "\n",
    "\n"
   ]
  }
 ],
 "metadata": {
  "colab": {
   "collapsed_sections": [],
   "name": "Session 3 - Conditionals if-elif-else.ipynb",
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  "interpreter": {
   "hash": "d8170c110657fe2404806e39cd19d1069764f0900149c4bfcf5e0c7a3bba27ab"
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   "language": "python",
   "name": "python3"
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   "codemirror_mode": {
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   "mimetype": "text/x-python",
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   "nbconvert_exporter": "python",
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