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除「甲」以二。名之曰「甲半」。 有數二。名之曰「戊」。恆為是。若「戊」等於「甲半」者乃止也。 有數二。名之曰「戌」。恆為是。若「戌」等於「甲半」者乃止也。
若「甲」非偶數,則「甲半」非整數也。然「戊」、「戌」終為整數,不得與「甲半」相等也。 此雖小繆,然現之于首頁,有如人之顏面,不妥也。 故斗膽進言,易二「「等於」」為「「不小於」」,則「甲」雖為奇數,乃至分數、無理數,循環必止於有限,阿基米德之公理也。
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Thanks! fixed: 97f0a4b
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吾以为公知所言极是哉
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若「甲」非偶數,則「甲半」非整數也。然「戊」、「戌」終為整數,不得與「甲半」相等也。
此雖小繆,然現之于首頁,有如人之顏面,不妥也。
故斗膽進言,易二「「等於」」為「「不小於」」,則「甲」雖為奇數,乃至分數、無理數,循環必止於有限,阿基米德之公理也。
The text was updated successfully, but these errors were encountered: