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use hrdata; SELECT * FROM hrdata.hr; ALTER TABLE hr CHANGE COLUMN id emp_id VARCHAR(20) NULL;

DESCRIBE hr; SELECT birthdate from hr; SELECT DATE_FORMAT (birthdate,'%M/%d/%Y') FROM hr;

SELECT hire_date from hr; SELECT DATE_FORMAT (hire_date,'%M/%d/%Y') FROM hr; UPDATE hr SET hire_date = DATE_FORMAT(STR_TO_DATE(hire_date, '%m/%d/%Y'), '%Y-%m-%d');

SELECT str_to_date(hire_date,'%m/%d/%y') from hr;

SELECT str_to_date(birthdate,'%m/%d/%y') from hr; UPDATE hr SET birthdate = STR_TO_DATE( birthdate,'%m/%d/%y');

UPDATE hr SET birthdate = DATE_FORMAT(STR_TO_DATE(birthdate, '%m/%d/%Y'), '%Y-%m-%d');

ALTER TABLE hr MODIFY COLUMN birthdate DATE; DESCRIBE hr;

ALTER TABLE hr MODIFY COLUMN hire_date DATE; DESCRIBE hr;

SET sql_safe_updates = 0;

select termdate from hr; update hr SET termdate = DATE(str_to_date(termdate,'%Y-%m-%d %H:%i:%s UTC')) WHERE termdate IS NOT NULL AND termdate!='';

UPDATE hr SET termdate = NOT NULL WHERE termdate ='';

ALTER TABLE hr MODIFY COLUMN termdate DATE;

SELECT birthdate,age FROM hr; ALTER TABLE hr ADD COLUMN age INT ;

UPDATE hr SET age = TIMESTAMPDIFF(YEAR,birthdate,CURDATE());

SELECT MIN(age) AS youngest, MAX(age) AS oldest FROM hr;

QUESTIONS
1. what is the gender breakdown of employees in the company?

select *from hrdata. hr;

SELECT gender,count(*) AS count FROM hr
WHERE termdate is NULL GROUP BY gender;

what is the race breakdown of employees in the company?

SELECT race, COUNT(*) AS count FROM hr WHERE termdate is NULL GROUP BY race;

what is the age distribution of employees in the company?

SELECT CASE WHEN age >=18 AND age <=24 THEN '18-24' WHEN age >=25 AND age <=35 THEN '25-34' WHEN age >=35 AND age <=44 THEN '35-44' WHEN age >=45 AND age <=54 THEN '45-54' WHEN age >=55 AND age <=64 THEN '55-64' ELSE '64+' END AS age_group, COUNT(*) AS count FROM hr WHERE termdate IS null GROUP BY age_group ORDER BY age_group;

###How many employees work HQ vs remote
SELECT  location ,COUNT(*) AS count
FROM hr
WHERE termdate IS NULL
GROUP BY location;

### What is the average term of employees who have been terminated
SELECT  ROUND(AVG(YEAR(termdate)-YEAR(hire_date)),0) AS length_emp
FROM hr
WHERE termdate IS NOT NUll AND termdate <= curdate();
### How does the gender distribution vary accross dept and job titles
select * from hr;
SELECT department,jobtitle,gender,count(*)
FROM hr
WHERE termdate IS NOT NULL
GROUP BY department,jobtitle,gender
ORDER BY department,jobtitle,gender;
### What is the distribution of jobtitles across the company
SELECT jobtitle ,count(*) AS count

FROM hr
WHERE termdate IS  NULL
GROUP BY jobtitle;

## Which dept has thehighest turnover/termination rate

SELECT department,
         count(*) AS total_count,
		  count(CASE 
                    WHEN termdate IS NOT NULL AND termdate <= curdate() THEN 1
                    END) AS terminated_count,
		   ROUND((count( CASE 
                    WHEN termdate IS NOT NULL AND termdate <= curdate() THEN 1
                    END)/count(*))*100,2) AS termination_rate
			FROM hr
            GROUP BY department
			ORDER BY termination_rate DESC;
            
        #### What is the distribution of employees across location state

SELECT location_state,count(*) count FROM hr WHERE termdate IS NULL GROUP BY location_state;

How has the companys employees count changed on hire date and termdate?

SELECT year, hires, terminations, hires-terminations AS net_change, (terminations/hires)100 AS change_percent FROM( SELECT year(hire_date) AS year, count() AS hires, SUM(CASE WHEN termdate IS NOT NULL AND termdate <= curdate() THEN 1 END) AS terminations

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