🌊 - Kim #17
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CheezItMan
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Apr 28, 2021
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| # Time Complexity: O(n) where n is the number of chars | ||
| # Space Complexity: O(n) where n is the number of words | ||
| def grouped_anagrams(strings) |
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👍 Interesting solution, the time complexity is O(n) if the words are pretty short, if they're unlimited in length the time complexity is O(nm) where m is the length of the longest string.
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| # Time Complexity: O(n log n) | ||
| # Space Complexity: O(n) | ||
| def top_k_frequent_elements(list, k) |
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| # Time Complexity: O(1) | ||
| # Space Complexity: O(n) | ||
| def valid_sudoku(table) |
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👍 I would say the time/space complexities are both O(1) since Sudoku never gets bigger than 9x9.
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