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Scissors - Araceli #41
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Original file line number | Diff line number | Diff line change |
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@@ -1,8 +1,42 @@ | ||
from heaps.min_heap import MinHeap | ||
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def heap_sort(list): | ||
def heap_sort(arr): | ||
""" This method uses a heap to sort an array. | ||
Time Complexity: ? | ||
Space Complexity: ? | ||
Time Complexity: O (log n) | ||
Space Complexity: O(1) | ||
""" | ||
pass | ||
n = len(arr) | ||
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# Build a maxheap. | ||
# Since last parent will be at ((n//2)-1) we can start at that location. | ||
for i in range(n // 2 - 1, -1, -1): | ||
heapify(arr, n, i) | ||
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# One by one extract elements | ||
for i in range(n-1, 0, -1): | ||
arr[i], arr[0] = arr[0], arr[i] # swap | ||
heapify(arr, i, 0) | ||
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return arr | ||
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def heapify(arr, n, i): | ||
largest = i # Initialize largest as root | ||
left = 2 * i + 1 # left = 2*i + 1 | ||
right = 2 * i + 2 # right = 2*i + 2 | ||
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# See if left child of root exists and is | ||
# greater than root | ||
if left < n and arr[i] < arr[left]: | ||
largest = left | ||
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# See if right child of root exists and is | ||
# greater than root | ||
if right < n and arr[largest] < arr[right]: | ||
largest = right | ||
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# Change root, if needed | ||
if largest != i: | ||
arr[i],arr[largest] = arr[largest],arr[i] # swap | ||
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# Heapify the root. | ||
heapify(arr, n, largest) |
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@@ -10,8 +10,6 @@ def __str__(self): | |
def __repr__(self): | ||
return str(self.value) | ||
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class MinHeap: | ||
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def __init__(self): | ||
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@@ -21,21 +19,35 @@ def __init__(self): | |
def add(self, key, value = None): | ||
""" This method adds a HeapNode instance to the heap | ||
If value == None the new node's value should be set to key | ||
Time Complexity: ? | ||
Space Complexity: ? | ||
Time Complexity: O(log n) | ||
Space Complexity: O(1) | ||
""" | ||
Comment on lines
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 However this is O(log n) for space complexity because |
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pass | ||
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if value == None: | ||
value = key | ||
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node = HeapNode(key, value) | ||
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self.store.append(node) | ||
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self.heap_up(len(self.store) - 1) | ||
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def remove(self): | ||
""" This method removes and returns an element from the heap | ||
maintaining the heap structure | ||
Time Complexity: ? | ||
Space Complexity: ? | ||
Time Complexity: O(log n) | ||
Space Complexity: O(1) | ||
Comment on lines
35
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 However space complexity is O(log n) due to the recursive call stack. |
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""" | ||
pass | ||
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if len(self.store) == 0: | ||
return None | ||
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self.swap(0, len(self.store) - 1) | ||
min = self.store.pop() | ||
self.heap_down(0) | ||
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return min.value | ||
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def __str__(self): | ||
""" This method lets you print the heap, when you're testing your app. | ||
""" | ||
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@@ -46,11 +58,12 @@ def __str__(self): | |
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def empty(self): | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 |
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""" This method returns true if the heap is empty | ||
Time complexity: ? | ||
Space complexity: ? | ||
Time complexity: O(log n) | ||
Space complexity: O(log n) | ||
""" | ||
pass | ||
self.store = [] | ||
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return self.store | ||
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def heap_up(self, index): | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 However time/space complexity are both O(log n) due to recursion. |
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""" This helper method takes an index and | ||
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@@ -59,18 +72,41 @@ def heap_up(self, index): | |
property is reestablished. | ||
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This could be **very** helpful for the add method. | ||
Time complexity: ? | ||
Space complexity: ? | ||
Time complexity: O(1) | ||
Space complexity: O(1) | ||
""" | ||
pass | ||
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if index == 0: | ||
return index | ||
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parent_index = (index - 1) // 2 | ||
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if self.store[parent_index].key > self.store[index].key: | ||
self.swap(parent_index, index) | ||
self.heap_up(parent_index) | ||
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def heap_down(self, index): | ||
""" This helper method takes an index and | ||
moves the corresponding element down the heap if it's | ||
larger than either of its children and continues until | ||
the heap property is reestablished. | ||
""" | ||
Comment on lines
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 |
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pass | ||
arr = self.store | ||
left_child = index * 2 + 1 | ||
right_child = index * 2 + 2 | ||
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if left_child < len(arr): | ||
if right_child < len(arr): | ||
if arr[left_child].key < arr[right_child].key: | ||
less = left_child | ||
else: | ||
less = right_child | ||
else: | ||
less = left_child | ||
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if arr[index].key > arr[less].key: | ||
self.swap(index, less) | ||
self.heap_down(less) | ||
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def swap(self, index_1, index_2): | ||
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👍 Awesome work an O(1) heapsort solution. Nice work.