Calculate the default timeout correctly

Due to a unit mix-up, the default timeout was only set to 1/60 of the intended time period, which occasionally causes errors in large images that you have to find first.
solth · Oct 31, 2024 · 300f949 · 300f949
1 parent bc0970f
commit 300f949
Showing 1 changed file with 2 additions and 2 deletions.
diff --git a/Kitodo-ImageManagement/src/main/java/org/kitodo/imagemanagement/ConvertRunner.java b/Kitodo-ImageManagement/src/main/java/org/kitodo/imagemanagement/ConvertRunner.java
@@ -51,7 +51,7 @@ class ConvertRunner {
     /**
      * Default timeout.
      */
-    private static final int DEFAULT_TIMEOUT_MINS = (int) TimeUnit.MINUTES.convert(2, TimeUnit.HOURS);
+    private static final int DEFAULT_TIMEOUT_SECS = (int) TimeUnit.SECONDS.convert(2, TimeUnit.HOURS);
 
     /**
      * {@code convert} command, optionally with full path.
@@ -72,7 +72,7 @@ void run(IMOperation commandLine) throws IOException {
         OutputStream outAndErr = new ByteArrayOutputStream();
         executor.setStreamHandler(new PumpStreamHandler(outAndErr));
 
-        long timeoutMillis = 1000L * KitodoConfig.getIntParameter(ParameterImageManagement.TIMEOUT_SEC, DEFAULT_TIMEOUT_MINS);
+        long timeoutMillis = 1000L * KitodoConfig.getIntParameter(ParameterImageManagement.TIMEOUT_SEC, DEFAULT_TIMEOUT_SECS);
         executor.setWatchdog(new ExecuteWatchdog(timeoutMillis));
 
         CommandLine command;