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Exercises from the Incredible Proof Machine, translated into Java by the power of Curry-Howard.

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The Curry-Howard Isomorphism presents:

The Incredible Proof Machine... translated to Java 6

Say what?

The Incredible Proof Machine (http://incredible.nomeata.de/) is a fantastic way to learn about logical proofs, and a lot of fun. It's a great training exercise for programmers.

The Curry-Howard isomorphism states that proofs in a logic system correspond to programs in a programming language. So, if you translate a theorem into types, if you can inhabit this type, then you've proven the theorem.

This repository translates most of the theorems in the Incredible Proof Machine into Java 6 methods. Your task is to implement the methods in order to prove the theorem.

Why Java 6?

Mostly because it's what I'm most familiar with.

I also want to show that, despite Java's limitations, it does have a reasonable static type system, which can be used to prove theorems.

More importantly, you can use Java's type system to prove properties of your own programs and prevent bugs. Every Java programmer should remember this.

But... I don't have lambda expressions

interface F<A, B> 

encodes a lambda expression using a single-function interface. Use that.

If you want to convert the exercises to Java 8 to use lambdas, feel free. I'd love to have a Java 8 branch or fork.

The rules

You are to use a "safe" subset of Java. This means:

  • No exceptions
  • No nulls
  • No equals, hashCode, clone or any other method on java.lang.Object
  • No var-args
  • No arrays
  • No inheritance from classes - only interfaces
  • No variance annotations
  • No missing type parameters (unless inferred)
  • No non-final params, classes, variables
  • No recursion
  • No casting, instanceof, reflection
  • No mocks or proxies
  • No for, while, goto, break, continue
  • No side effects

What IDE should I use?

The project is set up for IntelliJ, but use whatever you'd like.

How does the correspondence work in Java?

The axioms are parameters to the function; the goal is the return type.

a ∧ b <==> Pair<A, B>
a ∨ b <==> Either<A, B>
a → b <==> F<A, B> (i.e. a function)
⊥     <==> java.lang.Void (a type with no values)

Where are my blocks?

     +-----------------+
 X  -|              ∧  |- X∧Y   ===  Pair.p  
 Y  -|                 |
     +-----------------+


     +-----------------+
X∧Y -| ∧               |- X     ===  Pair.x  
     |                 |- Y          Pair.y
     +-----------------+


     +---+         +---+
     |   |- X   Y -| → |- X→Y   ===  new F<X, Y>() {...}
     |   |_________|   |
     |                 |
     +-----------------+


     +-----------------+
X→Y -| →               |- Y     ===  F.apply  
  X -|                 |
     +-----------------+


     +-----------------+
  X -|            .∨   |- X∨Y     ===  Either.<X,Y>x  
     |                 |
     +-----------------+


     +-----------------+
  Y -|            ∨.   |- X∨Y     ===  Either.<X,Y>y  
     |                 |
     +-----------------+


     +---+         +---+
     |   |- X   P -|   |  
X∨Y -| ∨ +---------+   |- P       === Either.<P>fold
     |   +----------   |
     |   |- Y   P -|   |
     +---+         +---+


     +-----------------+
  ⊥ -|  ⊥              |- P       ===  V.<P>absurd(Void)  
     +-----------------+


     +-----------------+
     |      TND        |- P∨(P→⊥) ===  TND.<P>tnd()
     +-----------------+

What's with the "fold" in Either?

This is called Church Encoding. It's a way of encoding a closed sum type a.k.a. tagged union type.

How do I know my answer's right?

The theorem has been proven if you've followed The Rules and your code compiles.

Why can't Java's infer this type?

Java's type inference isn't real flash. You may need to put in explicit type parameters in some places.

Why do some of the axioms throw exceptions?

While the types in these exercises are all expressible in Java, some of the values of these types are not. It doesn't matter, however - your job is to assume the axioms are true and construct proofs based on them. So long as you don't use exceptions in your proofs.

Where are sessions 6 and 7?

Sessions 6 and 7 use universal and existential quantifiers (∀ and ∃), which correspond to Π and Σ types in a dependently-typed programming language. Sadly, Java is not dependently-typed.

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Exercises from the Incredible Proof Machine, translated into Java by the power of Curry-Howard.

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