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CheezItMan
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Oct 17, 2019
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| # Time Complexity: O(n) where n is the length of nums | ||
| # Space Complexity: O(1) | ||
| def max_sub_array(nums) |
| # Time complexity: ? | ||
| # Space Complexity: ? | ||
| # Time complexity: O(n) where n is the size of num | ||
| # Space Complexity: O(n) bc I am making an array dependent on size of num, n |
| end | ||
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| p = Array.new(num) |
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Just note, p isn't exactly a meaning ful variable name, although I recognize it is from the formula.
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